If the digits of the number 5726489 are arran | vedclass

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(D) The original number is $5726489$.Arranging the digits in ascending order:Original: $5, 7, 2, 6, 4, 8, 9$Sorted: $2, 4, 5, 6, 7, 8, 9$Comparing the

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Three

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(D) The original number is $5726489$.Arranging the digits in ascending order:Original: $5, 7, 2, 6, 4, 8, 9$Sorted: $2, 4, 5, 6, 7, 8, 9$Comparing the positions:Original: $5, 7, 2, 6, 4, 8, 9$Sorted: $2, 4, 5, 6, 7, 8, 9$Comparing digit by digit:$1^{st}$ position: $5 
eq 2$$2^{nd}$ position: $7 
eq 4$$3^{rd}$ position: $2 
eq 5$$4^{th}$ position: $6 = 6$ (Same)$5^{th}$ position: $4 
eq 7$$6^{th}$ position: $8 = 8$ (Same)$7^{th}$ position: $9 = 9$ (Same)The digits that remain at the same position are $6, 8,$ and $9$.Therefore,there are $3$ digits that remain at the same position.

If the digits of the number $5726489$ are arranged in ascending order,how many digits will remain at the same position?

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