If the direction cosines of a line are left( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The direction cosines of a line are given as $l = \frac{1}{c}$,$m = \frac{1}{c}$,and $n = \frac{1}{c}$.We know that for any line,the sum of the sq

Vedclass · Accepted Answer

$c = \pm \sqrt{3}$

Vedclass · Answer

(B) The direction cosines of a line are given as $l = \frac{1}{c}$,$m = \frac{1}{c}$,and $n = \frac{1}{c}$.We know that for any line,the sum of the squares of its direction cosines is always equal to $1$,i.e.,$l^2 + m^2 + n^2 = 1$.Substituting the given values,we get:$\left( \frac{1}{c} \right)^2 + \left( \frac{1}{c} \right)^2 + \left( \frac{1}{c} \right)^2 = 1$$\frac{1}{c^2} + \frac{1}{c^2} + \frac{1}{c^2} = 1$$\frac{3}{c^2} = 1$$c^2 = 3$$c = \pm \sqrt{3}$.

If the direction cosines of a line are $\left( \frac{1}{c}, \frac{1}{c}, \frac{1}{c} \right)$,then

Similar Questions

If the direction cosines of a line are $\frac{1}{c}, \frac{1}{c}, \frac{1}{c}$,then:

If the direction cosines of two lines are such that $2l + m + 2n = 0$ and $3l^2 + 5m^2 - 11n^2 = 0$,then the angle between the two lines is

If the direction ratios $(d.r.'s)$ of two lines are connected by the relations $a-b+c=0$ and $a^2-b^2+2c^2=0$, and $\theta$ is the angle between these lines, then $\cos \theta = $

What are the direction cosines of the line joining the points $(4, 3, -5)$ and $(-2, 1, -8)$?

$A$ line in the $3-$dimensional space makes an angle $\theta \left( 0 < \theta \le \frac{\pi}{2} \right)$ with both the $x$ and $y$ axes. Then the set of all values of $\theta$ is the interval

Vedclass Test Series

Exam Paper Generator

Online Exam Module