If the distance between Na^{+} and Cl^{-} ion | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a sodium chloride $(NaCl)$ crystal, the structure is $fcc$ (face-centered cubic).$Cl^{-}$ ions are present at the corners and face centers, whi

Vedclass · Accepted Answer

$2 Y \ pm$

Vedclass · Answer

(B) In a sodium chloride $(NaCl)$ crystal, the structure is $fcc$ (face-centered cubic).$Cl^{-}$ ions are present at the corners and face centers, while $Na^{+}$ ions occupy all octahedral voids.The distance between the nearest $Na^{+}$ and $Cl^{-}$ ions is equal to half of the edge length $(a)$ of the unit cell.Given, distance between $Na^{+}$ and $Cl^{-} = Y \ pm$.Therefore, $Y = \frac{a}{2}$.This implies that the edge length $a = 2 Y \ pm$.Thus, option $(b)$ is the correct answer.

If the distance between $Na^{+}$ and $Cl^{-}$ ions in sodium chloride crystal is '$Y$' $pm$, the length of the edge of the unit cell will be:

Similar Questions

Which of the following does $NOT$ have a triclinic structure?

Bravais lattices are of (in $types$)

The unit cell present in the crystal lattice of diamond is

Identify the type of unit cell containing a single particle.

The parameters $a = b = c$ and $\alpha = \beta = \gamma \neq 90^\circ$ belong to which crystal system?

Vedclass Test Series

Exam Paper Generator

Online Exam Module