If the distance between two consecutive base | vedclass

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(D) The length of $DNA$ is calculated by multiplying the distance between two consecutive base pairs by the total number of base pairs.Given:Distance

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$2.2 \, meters$

Vedclass · Answer

(D) The length of $DNA$ is calculated by multiplying the distance between two consecutive base pairs by the total number of base pairs.Given:Distance between two base pairs = $0.34 \, nm = 0.34 	imes 10^{-9} \, m$.Total number of base pairs = $6.6 	imes 10^{9} \, bp$.Length of $DNA$ = $(	ext{Distance between two base pairs}) 	imes (	ext{Total number of base pairs})$.Length of $DNA$ = $(0.34 	imes 10^{-9} \, m) 	imes (6.6 	imes 10^{9} \, bp)$.Length of $DNA$ = $0.34 	imes 6.6 \, m = 2.244 \, m$.Therefore,the length of the $DNA$ is approximately $2.2 \, meters$.

If the distance between two consecutive base pairs is $0.34 \, nm$ and the total number of base pairs of a $DNA$ double helix in a typical mammalian cell is $6.6 \times 10^{9} \, bp$,then the length of the $DNA$ is approximately:

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