If the distance between two objects is double | vedclass

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(D) According to Newton's law of universal gravitation,the force $F$ between two objects of masses $m_1$ and $m_2$ separated by a distance $r$ is give

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becomes one-fourth

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(D) According to Newton's law of universal gravitation,the force $F$ between two objects of masses $m_1$ and $m_2$ separated by a distance $r$ is given by the formula: $F = G \frac{m_1 m_2}{r^2}$.Here,$G$ is the universal gravitational constant.If the distance $r$ is doubled,the new distance becomes $r' = 2r$.The new gravitational force $F'$ will be: $F' = G \frac{m_1 m_2}{(2r)^2} = G \frac{m_1 m_2}{4r^2}$.This can be rewritten as: $F' = \frac{1}{4} 	imes (G \frac{m_1 m_2}{r^2}) = \frac{1}{4} F$.Therefore,the gravitational force becomes one-fourth of its original value.

If the distance between two objects is doubled,the gravitational force between them :

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