If the eccentricity of a hyperbola is frac{5} | vedclass

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(B) Let the eccentricity of the hyperbola be $e_1 = \frac{5}{3}$ and the eccentricity of its conjugate hyperbola be $e_2$.For a hyperbola and its conj

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$\frac{5}{4}$

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(B) Let the eccentricity of the hyperbola be $e_1 = \frac{5}{3}$ and the eccentricity of its conjugate hyperbola be $e_2$.For a hyperbola and its conjugate,the relationship between their eccentricities is given by $\frac{1}{e_1^2} + \frac{1}{e_2^2} = 1$.Substituting the value of $e_1$:$\frac{1}{(5/3)^2} + \frac{1}{e_2^2} = 1$$\frac{9}{25} + \frac{1}{e_2^2} = 1$$\frac{1}{e_2^2} = 1 - \frac{9}{25} = \frac{16}{25}$$e_2^2 = \frac{25}{16}$$e_2 = \frac{5}{4}$Thus,the eccentricity of the conjugate hyperbola is $\frac{5}{4}$.

If the eccentricity of a hyperbola is $\frac{5}{3}$,then the eccentricity of its conjugate hyperbola is

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