If the emf of an AC source is given by E = 6 | vedclass

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(B) The given emf is $E = 6 \sin \omega t + 4 \sin 2 \omega t 	ext{ V}$.For a non-sinusoidal periodic waveform $E = E_1 \sin \omega t + E_2 \sin 2 \o

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$\sqrt{26} 	ext{ V}$

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(B) The given emf is $E = 6 \sin \omega t + 4 \sin 2 \omega t 	ext{ V}$.For a non-sinusoidal periodic waveform $E = E_1 \sin \omega t + E_2 \sin 2 \omega t + \dots$,the rms value is given by $E_{	ext{rms}} = \sqrt{\frac{E_1^2 + E_2^2 + \dots}{2}}$.Here,$E_1 = 6 	ext{ V}$ and $E_2 = 4 	ext{ V}$.Substituting these values into the formula:$E_{	ext{rms}} = \sqrt{\frac{6^2 + 4^2}{2}}$$E_{	ext{rms}} = \sqrt{\frac{36 + 16}{2}}$$E_{	ext{rms}} = \sqrt{\frac{52}{2}}$$E_{	ext{rms}} = \sqrt{26} 	ext{ V}$.Thus,the rms value of the emf is $\sqrt{26} 	ext{ V}$.

If the emf of an $AC$ source is given by $E = 6 \sin \omega t + 4 \sin 2 \omega t \text{ V}$,then the rms value of the emf is

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