If the energy released in the fission of one nucleus is $200 \, MeV$, then the number of nuclei required per second in a power plant of $16 \, kW$ will be:

  • A
    $0.5 \times 10^{14}$
  • B
    $0.5 \times 10^{12}$
  • C
    $5 \times 10^{12}$
  • D
    $5 \times 10^{14}$

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