If the equations $3x^2 + 2hxy - 3y^2 = 0$ and $3x^2 + 2hxy - 3y^2 + 2x - 4y + c = 0$ represent the four sides of a square,then $\frac{h}{c} =$

  • A
    $\frac{1}{4}$
  • B
    $-\frac{2}{3}$
  • C
    $-3$
  • D
    $-4$

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