If the following system of linear equations
$2x + y + z = 5$
$x - y + z = 3$
$x + y + az = b$
has no solution,then :

  • A
    $a = -\frac{1}{3}, b \neq \frac{7}{3}$
  • B
    $a \neq \frac{1}{3}, b = \frac{7}{3}$
  • C
    $a \neq -\frac{1}{3}, b = \frac{7}{3}$
  • D
    $a = \frac{1}{3}, b \neq \frac{7}{3}$

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