If the force is given by F = at + bt^2,where | vedclass

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(B) According to the principle of homogeneity of dimensions,the dimensions of each term in a physical equation must be the same.Given the equation $F

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$[MLT^{-3}], [MLT^{-4}]$

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(B) According to the principle of homogeneity of dimensions,the dimensions of each term in a physical equation must be the same.Given the equation $F = at + bt^2$,where $F$ is force and $t$ is time.The dimension of force $F$ is $[MLT^{-2}]$.For the first term: $[at] = [F]$$[a] = [F] / [t] = [MLT^{-2}] / [T] = [MLT^{-3}]$.For the second term: $[bt^2] = [F]$$[b] = [F] / [t^2] = [MLT^{-2}] / [T^2] = [MLT^{-4}]$.Thus,the dimensions of $a$ and $b$ are $[MLT^{-3}]$ and $[MLT^{-4}]$ respectively.

If the force is given by $F = at + bt^2$,where $t$ is time,the dimensions of $a$ and $b$ are:

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