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(A) Let the third number be $x$.Then,the first number $= 0.07x$ and the second number $= 0.28x$.We need to find what percentage the first number is of

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) Let the third number be $x$.Then,the first number $= 0.07x$ and the second number $= 0.28x$.We need to find what percentage the first number is of the second number.Required percentage $= (\frac{	ext{First number}}{	ext{Second number}}) 	imes 100 \%$.$= (\frac{0.07x}{0.28x}) 	imes 100 \%$.$= (\frac{7}{28}) 	imes 100 \%$.$= \frac{1}{4} 	imes 100 \% = 25 \%$.

If the given two numbers are respectively $7 \%$ and $28 \%$ of a third number,then what percentage is the first of the second?

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