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(A) For an amplitude-modulated wave,the bandwidth required for one channel is twice the maximum frequency of the modulating signal.Bandwidth $(BW)$ pe

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$15$

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(A) For an amplitude-modulated wave,the bandwidth required for one channel is twice the maximum frequency of the modulating signal.Bandwidth $(BW)$ per channel $= 2 	imes f_{max} = 2 	imes 5\, kHz = 10\, kHz$.The total available bandwidth is $150\, kHz$.The number of stations that can be accommodated is given by the ratio of the total bandwidth to the bandwidth per channel.Number of stations $= \frac{	ext{Total Bandwidth}}{	ext{Bandwidth per channel}} = \frac{150\, kHz}{10\, kHz} = 15$.

If the highest modulating frequency of the wave is $5\, kHz$,the number of stations that can be accommodated in a $150\, kHz$ bandwidth are

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