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(B) Given,the highest modulating frequency,$f_m = 5 kHz = 5 	imes 10^3 Hz$.For an amplitude-modulated wave,the bandwidth required for one station is

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$15$

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(B) Given,the highest modulating frequency,$f_m = 5 kHz = 5 	imes 10^3 Hz$.For an amplitude-modulated wave,the bandwidth required for one station is $BW = 2 f_m$.Therefore,$BW = 2 	imes 5 kHz = 10 kHz = 10^4 Hz$.The total available bandwidth is $f = 150 kHz = 150 	imes 10^3 Hz$.The number of stations that can be accommodated is given by the ratio of the total bandwidth to the bandwidth per station.Number of stations $= \frac{f}{BW} = \frac{150 kHz}{10 kHz} = 15$.

If the highest modulating frequency of the wave is $5 kHz$,then the number of stations that can be accommodated in a $150 kHz$ bandwidth is

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