If the initial velocity of a projectile is do | vedclass

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(C) The formula for the maximum height $(H)$ reached by a projectile is given by: $H = \frac{u^2 \sin^2 	heta}{2g}$ From this expression,we can see t

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Be quadrupled

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(C) The formula for the maximum height $(H)$ reached by a projectile is given by: $H = \frac{u^2 \sin^2 	heta}{2g}$ From this expression,we can see that the maximum height is directly proportional to the square of the initial velocity $(u)$: $H \propto u^2$ If the initial velocity is doubled $(u' = 2u)$,the new maximum height $(H')$ becomes: $H' \propto (2u)^2 = 4u^2$ Therefore,$H' = 4H$. Thus,the maximum height reached by the projectile will be quadrupled.

If the initial velocity of a projectile is doubled,keeping the angle of projection the same,the maximum height reached by it will:

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