If the length of a pendulum is made $9$ times and the mass of the bob is made $4$ times,then the value of the time period becomes:

The length of a simple pendulum is increased by $2\%$. Its time period will

The time period of a simple pendulum in a lift descending with constant acceleration $g$ is

$A$ simple pendulum of length $l_1$ has time period $T_1$. Another simple pendulum of length $l_2$ $(l_1 > l_2)$ has time period $T_2$. Then the time period of the pendulum of length $(l_1 - l_2)$ will be

$A$ simple pendulum of length $l$ and having a bob of mass $M$ is suspended in a car. The car is moving on a circular track of radius $R$ with a uniform speed $v$. If the pendulum makes small oscillations in a radial direction about its equilibrium position,what will be its time period?

The length of the seconds pendulum is decreased by $0.3 \ cm$ when it is shifted from place $A$ to place $B$. If the acceleration due to gravity at place $A$ is $981 \ cm/s^2$,the acceleration due to gravity at place $B$ is $($ Take $\pi^2 = 10$ $)$ (in $cm/s^2$)