If the lines represented by the equation 6x^2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given equation of the pair of lines is $6x^2 + 41xy - 7y^2 = 0$.Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we get $a = 6$,$

Vedclass · Accepted Answer

$-6/7$

Vedclass · Answer

(A) The given equation of the pair of lines is $6x^2 + 41xy - 7y^2 = 0$.Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we get $a = 6$,$2h = 41$,and $b = -7$.Let the slopes of the two lines be $m_1 = 	an \alpha$ and $m_2 = 	an \beta$.For a pair of lines $ax^2 + 2hxy + by^2 = 0$,the product of the slopes is given by $m_1 m_2 = \frac{a}{b}$.Substituting the values,we get $	an \alpha \cdot 	an \beta = \frac{6}{-7} = -\frac{6}{7}$.

If the lines represented by the equation $6x^2 + 41xy - 7y^2 = 0$ make angles $\alpha$ and $\beta$ with the $x$-axis,then $\tan \alpha \cdot \tan \beta = $

Similar Questions

If two of the lines represented by $2x^3+x^2y+y^3=0$ are mutually perpendicular,then the slope of the third line is

The separate equations of the lines represented by the pair of lines equation $x^2 + xy - 12y^2 = 0$ are

The slope of one of the pair of lines $2x^2 + hxy + 6y^2 = 0$ is thrice the slope of the other line. Then,$h = $

If $L{x^2} - 10xy + 12{y^2} + 5x - 16y - 3 = 0$ represents a pair of straight lines,then the value of $L$ is:

Which of the following equations does not represent a pair of lines?

Vedclass Test Series

Exam Paper Generator

Online Exam Module