If the magnetic susceptibility of a substance | vedclass

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(A) The relationship between relative permeability $\mu_r$ and magnetic susceptibility $\chi_m$ is given by the formula: $\mu_r = 1 + \chi_m$.Given th

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$8: 5$

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(A) The relationship between relative permeability $\mu_r$ and magnetic susceptibility $\chi_m$ is given by the formula: $\mu_r = 1 + \chi_m$.Given that the magnetic susceptibility $\chi_m = 0.6$.Substituting the value, we get: $\mu_r = 1 + 0.6 = 1.6$.We know that relative permeability $\mu_r$ is defined as the ratio of the permeability of the substance $\mu$ to the permeability of free space $\mu_0$, i.e.,$\mu_r = \frac{\mu}{\mu_0}$.Therefore, $\frac{\mu}{\mu_0} = 1.6$.Converting $1.6$ into a fraction: $1.6 = \frac{16}{10} = \frac{8}{5}$.Thus, the ratio of the permeability of the substance to the permeability of free space is $8:5$.

If the magnetic susceptibility of a substance is $0.6$, then the ratio of permeability of the substance and permeability of free space is

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