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(B) The magnification $(m)$ of a mirror is given by the ratio of the height of the image $(h')$ to the height of the object $(h)$,which is also equal

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(B) The magnification $(m)$ of a mirror is given by the ratio of the height of the image $(h')$ to the height of the object $(h)$,which is also equal to $(-\frac{v}{u})$.Given $m = -\frac{1}{3}$.$1$. The negative sign $(-)$ indicates that the image is real and inverted.$2$. The magnitude of magnification is $\frac{1}{3}$,which is less than $1$,indicating that the image is diminished.$3$. $A$ plane mirror always produces a virtual,erect image with a magnification of $+1$.$4$. $A$ convex mirror always produces a virtual,erect,and diminished image with a magnification between $0$ and $+1$.$5$. $A$ concave mirror can produce real,inverted,and diminished images when the object is placed beyond the center of curvature $(C)$.Therefore,the mirror must be a concave mirror.

If the magnification of an image formed by a mirror is $(-\frac{1}{3})$,what type of mirror is it?

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