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(D) The atomic mass of an atom is given by the sum of the number of protons and neutrons. The mass of an electron is negligible compared to protons an

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be reduced approximately by $25\%$

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(D) The atomic mass of an atom is given by the sum of the number of protons and neutrons. The mass of an electron is negligible compared to protons and neutrons.For $_6C^{12}$,the number of protons is $6$ and the number of neutrons is $12 - 6 = 6$.Original mass $\approx 6 	imes m_p + 6 	imes m_n$,where $m_p \approx m_n$.If the mass of a neutron is halved $(m_n' = 0.5 	imes m_n)$,the new mass becomes $\approx 6 	imes m_p + 6 	imes (0.5 	imes m_n) = 6 	imes m_p + 3 	imes m_n$.Since $m_p \approx m_n$,the new mass is approximately $9 	imes m_p$,which is $9/12 = 0.75$ times the original mass.This represents a reduction of $25\%$.

$(i) \ _{26}Fe^{54}, \ _{26}Fe^{56}, \ _{26}Fe^{58}$	$(a) \ \text{Isotopes}$
$(ii) \ _1H^3, \ _2He^3$	$(b) \ \text{Isotones}$
$(iii) \ _{32}Ge^{76}, \ _{33}As^{77}$	$(c) \ \text{Isoelectronic}$
$(iv) \ _{11}Na^+, \ _{12}Mg^{2+}$	$(d) \ \text{Isobars}$
$(v) \ _1H^1, \ _1D^2, \ _1T^3$

If the mass attributed to a neutron were halved and that attributed to the electron were doubled,the atomic mass of $_6C^{12}$ would

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