If the modal class of a frequency distribution is $70-85,$ then in the formula for mode,$l=$ ..........
- A$15$
- B$77.5$
- C$70$
- D$85$
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Similar Questions
The weight of coffee in $70$ packets is shown in the following table:
Weight (in $g$) Number of packets $200-201$ $12$ $201-202$ $26$ $202-203$ $20$ $203-204$ $9$ $204-205$ $2$ $205-206$ $1$
Determine the modal weight (in $g$).
| Weight (in $g$) | Number of packets |
| $200-201$ | $12$ |
| $201-202$ | $26$ |
| $202-203$ | $20$ |
| $203-204$ | $9$ |
| $204-205$ | $2$ |
| $205-206$ | $1$ |
Determine the modal weight (in $g$).
Easy
View SolutionFor the following distribution,the modal class is:
Marks Number of students Below $10$ $3$ Below $20$ $12$ Below $30$ $27$ Below $40$ $57$ Below $50$ $75$ Below $60$ $80$
| Marks | Number of students |
| Below $10$ | $3$ |
| Below $20$ | $12$ |
| Below $30$ | $27$ |
| Below $40$ | $57$ |
| Below $50$ | $75$ |
| Below $60$ | $80$ |
Easy
View SolutionFind the mode of the following frequency distribution:
Class $0-20$ $20-40$ $40-60$ $60-80$ $80-100$ $100-120$ Frequency $8$ $9$ $26$ $23$ $20$ $14$
| Class | $0-20$ | $20-40$ | $40-60$ | $60-80$ | $80-100$ | $100-120$ |
| Frequency | $8$ | $9$ | $26$ | $23$ | $20$ | $14$ |
Medium
View SolutionIn the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$c = \dots$
Easy
View SolutionFor the following data,the modal class is .... .
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ Frequency $7$ $16$ $25$ $32$ $20$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ |
| Frequency | $7$ | $16$ | $25$ | $32$ | $20$ |
Easy
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