If the normal to the curve $y = f(x)$ at the point $(4, 6)$ makes an angle $\frac{2\pi}{3}$ with the positive $x$-axis in the anticlockwise direction,then $f'(4)$ is:
- A$\sqrt{3}$
- B$-\sqrt{3}$
- C$\frac{1}{\sqrt{3}}$
- D$-\frac{1}{\sqrt{3}}$
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