If the nuclear radius of {}_{13}^{27}Al is 3. | vedclass

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(C) The nuclear radius $R$ is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant and $A$ is the mass number.For ${}_{13}^{27}Al$,$A_1 =

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$4.8$

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(C) The nuclear radius $R$ is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant and $A$ is the mass number.For ${}_{13}^{27}Al$,$A_1 = 27$ and $R_1 = 3.6 \, fm$.For ${}_{29}^{64}Cu$,$A_2 = 64$.Taking the ratio: $\frac{R_2}{R_1} = \left( \frac{A_2}{A_1} ight)^{1/3}$.Substituting the values: $\frac{R_2}{3.6} = \left( \frac{64}{27} ight)^{1/3}$.$\frac{R_2}{3.6} = \frac{4}{3}$.$R_2 = 3.6 	imes \frac{4}{3} = 1.2 	imes 4 = 4.8 \, fm$.

If the nuclear radius of ${}_{13}^{27}Al$ is $3.6 \, fm$,the approximate nuclear radius of ${}_{29}^{64}Cu$ in fermi is .......... $fm$.

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