If the number of uranium nuclei required per hour to produce a power of $64 \text{ kW}$ is $7.2 \times 10^{18}$, then the energy released per fission is

The energy released in an atom bomb is obtained from?

Nuclear fission is best explained by
[$AIPMT$ $2000$]

$A$ chain reaction is continuous due to

Two lithium nuclei in a lithium vapour at room temperature do not combine to form a carbon nucleus because

$A$ star has $100 \%$ helium composition. It starts to convert three ${ }^4 He$ into one ${ }^{12} C$ via the triple alpha process as ${ }^4 He + { }^4 He + { }^4 He \rightarrow { }^{12} C + Q$. The mass of the star is $2.0 \times 10^{32} \ kg$ and it generates energy at the rate of $5.808 \times 10^{30} \ W$. The rate of converting these ${ }^4 He$ nuclei to ${ }^{12} C$ is $n \times 10^{42} \ s^{-1}$,where $n$ is. . . . . . . [Take,mass of ${ }^4 He = 4.0026 \ u$,mass of ${ }^{12} C = 12 \ u$,$1 \ u = 1.66 \times 10^{-27} \ kg$,$c = 3 \times 10^8 \ m/s$]