If the numerator of a fraction is increased b | vedclass

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Question

(B) Let the original fraction be $\frac{x}{y}$.According to the problem,the numerator is increased by $120 \%$,so the new numerator is $x + 1.20x = 2.

Vedclass · Accepted Answer

$0.83$

Vedclass · Answer

(B) Let the original fraction be $\frac{x}{y}$.According to the problem,the numerator is increased by $120 \%$,so the new numerator is $x + 1.20x = 2.20x$.The denominator is increased by $350 \%$,so the new denominator is $y + 3.50y = 4.50y$.The new fraction is given as $\frac{2.20x}{4.50y} = \frac{11}{27}$.Simplifying the equation: $\frac{22x}{45y} = \frac{11}{27}$.Solving for $\frac{x}{y}$: $\frac{x}{y} = \frac{11}{27} 	imes \frac{45}{22} = \frac{1}{3} 	imes \frac{5}{2} = \frac{5}{6}$.Converting to decimal: $\frac{5}{6} \approx 0.833$.

If the numerator of a fraction is increased by $120 \%$ and the denominator is also increased by $350 \%$,then the fraction becomes $\frac{11}{27}$. What was the original fraction?

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