If the pair of straight lines xy-x-y+1=0 and | vedclass

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(B) The given pair of straight lines is $xy-x-y+1=0$.Factoring the expression: $x(y-1)-1(y-1)=0$,which gives $(x-1)(y-1)=0$.This represents two lines:

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$1$

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(B) The given pair of straight lines is $xy-x-y+1=0$.Factoring the expression: $x(y-1)-1(y-1)=0$,which gives $(x-1)(y-1)=0$.This represents two lines: $x=1$ and $y=1$.The point of intersection of these two lines is $(1, 1)$.Since the lines are concurrent with the line $ax+2y-3a=0$,the point $(1, 1)$ must satisfy the equation of the line $ax+2y-3a=0$.Substituting $x=1$ and $y=1$ into the equation: $a(1)+2(1)-3a=0$.$a+2-3a=0$.$-2a+2=0$.$2a=2$.$a=1$.

If the pair of straight lines $xy-x-y+1=0$ and the line $ax+2y-3a=0$ are concurrent,then $a$ is equal to

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