If the parabola y^2 = 4ax passes through the | vedclass

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(C) Given the parabola equation is $y^2 = 4ax$.Since it passes through the point $(1, -2)$,we substitute $x = 1$ and $y = -2$ into the equation:$(-2)^

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$x + y + 1 = 0$

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(C) Given the parabola equation is $y^2 = 4ax$.Since it passes through the point $(1, -2)$,we substitute $x = 1$ and $y = -2$ into the equation:$(-2)^2 = 4a(1)$$4 = 4a$$\Rightarrow a = 1$.Now,the equation of the parabola is $y^2 = 4x$.The equation of the tangent to the parabola $y^2 = 4ax$ at point $(x_1, y_1)$ is given by $yy_1 = 2a(x + x_1)$.Substituting $a = 1$,$x_1 = 1$,and $y_1 = -2$:$y(-2) = 2(1)(x + 1)$$-2y = 2(x + 1)$$-y = x + 1$$x + y + 1 = 0$.Thus,the required tangent is $x + y + 1 = 0$.

If the parabola $y^2 = 4ax$ passes through the point $(1, -2)$,then the tangent at this point is

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