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(D) The time period $T$ of a mass $m$ suspended from a spring with spring constant $k$ is given by the formula: $T = 2\pi \sqrt{\frac{m}{k}}$.Given th

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$4$

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(D) The time period $T$ of a mass $m$ suspended from a spring with spring constant $k$ is given by the formula: $T = 2\pi \sqrt{\frac{m}{k}}$.Given that for mass $m$,the time period $T_1 = 2 \ s$.So,$2 = 2\pi \sqrt{\frac{m}{k}}$.Now,for a new mass $m' = 4m$,the new time period $T_2$ is: $T_2 = 2\pi \sqrt{\frac{4m}{k}}$.We can rewrite this as: $T_2 = 2 	imes (2\pi \sqrt{\frac{m}{k}})$.Substituting the value of $T_1$ into the equation: $T_2 = 2 	imes T_1$.Since $T_1 = 2 \ s$,we get $T_2 = 2 	imes 2 \ s = 4 \ s$.

If the period of oscillation of mass $m$ suspended from a spring is $2 \ s$,then the period of oscillation of suspended mass $4m$ with the same spring will be: (in $s$)

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