If the potential difference across a capacito | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The energy stored in a capacitor is given by the formula $W = \frac{1}{2} CV^2$, where $C$ is the capacitance and $V$ is the potential difference.

Vedclass · Accepted Answer

$9$ : $1$

Vedclass · Answer

(D) The energy stored in a capacitor is given by the formula $W = \frac{1}{2} CV^2$, where $C$ is the capacitance and $V$ is the potential difference.Initial energy $W_1 = \frac{1}{2} CV_1^2$, where $V_1 = 5 \,V$.Final energy $W_2 = \frac{1}{2} CV_2^2$, where $V_2 = 15 \,V$.The ratio of final energy to initial energy is $\frac{W_2}{W_1} = \frac{\frac{1}{2} CV_2^2}{\frac{1}{2} CV_1^2} = \left(\frac{V_2}{V_1}\right)^2$.Substituting the values, we get $\frac{W_2}{W_1} = \left(\frac{15}{5}\right)^2 = (3)^2 = 9$.Therefore, the ratio is $9 : 1$.

If the potential difference across a capacitor is increased from $5 \,V$ to $15 \,V$, then the ratio of final energy to initial energy stored in the capacitor is

Similar Questions

The energy stored in a capacitor of capacitance $10 \mu F$ when charged to a potential of $6 \text{ kV}$ is: (in $\text{ J}$)

When an uncharged capacitor is connected to a battery to charge it fully,

$A$ capacitor of capacitance $C$ has stored energy $W$ and charge $Q$. If the charge is increased to $2Q$,what will be the new stored energy?

The energy stored in a capacitor is in the form of

$A$ parallel plate capacitor is connected to a battery. The plates are pulled apart with a uniform speed. If $x$ is the separation between the plates,the time rate of change of electrostatic energy of the capacitor is proportional to

Vedclass Test Series

Exam Paper Generator

Online Exam Module