If the probability distribution of a random variable $X$ is as follows,then the mean of $X$ is:
$X = x_i$$-1$$0$$1$$2$
$P(X = x_i)$$k^3$$2k^3 + k$$4k - 10k^2$$4k - 1$

  • A
    $\frac{193}{27}$
  • B
    $\frac{25}{27}$
  • C
    $\frac{23}{27}$
  • D
    $\frac{83}{27}$

Explore More

Similar Questions

In a communication network, $98 \%$ of messages are transmitted with no error. If a random variable $X$ denotes the number of incorrectly transmitted messages, then the probability that at most one message is transmitted incorrectly out of $500$ messages sent, is

For a Poisson variate $X$,if $P(X=2)=3 P(X=3)$,then the mean of $X$ is:

Let $X$ represent the difference between the number of heads and the number of tails obtained when a coin is tossed $6$ times. What are the possible values of $X$?

The probability distribution of a discrete random variable $X$ is given by the following table:
$X$$1$$2$$3$$4$$5$$6$
$P(X)$$K$$2K$$3K$$4K$$5K$$6K$

Find the value of $P(2 < X < 6)$.

If a random variable $X$ has the p.d.f. $f(x) = \begin{cases} \frac{k}{x^2+1} & , \text{if } 0 < x < \infty \\ 0 & , \text{otherwise} \end{cases}$,then the c.d.f. of $X$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo