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(B) Given, radius of an atom in a body-centered cubic $(bcc)$ unit cell, $r = 173.2 \ pm = 173.2 	imes 10^{-10} \ cm$.For a $bcc$ structure, the rela

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$6.4 	imes 10^{-23}$

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(B) Given, radius of an atom in a body-centered cubic $(bcc)$ unit cell, $r = 173.2 \ pm = 173.2 	imes 10^{-10} \ cm$.For a $bcc$ structure, the relationship between edge length $a$ and radius $r$ is $\sqrt{3} \cdot a = 4r$.Therefore, $a = \frac{4r}{\sqrt{3}} = \frac{4 	imes 173.2 	imes 10^{-10}}{1.732} \ cm$.$a = 4 	imes 100 	imes 10^{-10} \ cm = 400 	imes 10^{-10} \ cm = 4 	imes 10^{-8} \ cm$.The volume of the unit cell $V = a^3 = (4 	imes 10^{-8} \ cm)^3$.$V = 64 	imes 10^{-24} \ cm^3 = 6.4 	imes 10^{-23} \ cm^3$.

If the radius of an atom of an element which forms a body centered cubic unit cell is $173.2 \ pm$, the volume of the unit cell in $cm^3$ is:

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