(A) The relationship between conductivity $(\kappa)$,resistance $(R)$,and cell constant $(G^*)$ is given by: $\kappa = \frac{1}{R} \times G^*$Therefor

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The relationship between conductivity $(\kappa)$,resistance $(R)$,and cell constant $(G^*)$ is given by: $\kappa = \frac{1}{R} \times G^*$Therefore,$G^* = \kappa \times R$Given values are: $\kappa = 0.013 \ S \ cm^{-1}$ and $R = 300 \ \Omega$Substituting these values: $G^* = 0.013 \ S \ cm^{-1} \times 300 \ \Omega = 3.9 \ cm^{-1}$.

Class 12 Chemistry Electrochemistry Conductor and Conductance and Cell constant

Medium

If the resistance of $0.1 \ M \ KCl$ solution in a conductance cell is $300 \ \Omega$ and conductivity is $0.013 \ S \ cm^{-1}$,then the value of cell constant is

AP EAMCET 2021 All AP EAMCET

A
$3.9 \ cm^{-1}$
B
$39 \ m^{-1}$
C
$3.9 \ m^{-1}$
D
$0.39 \ cm^{-1}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Electrochemistry

Subtopic

Conductor and Conductance and Cell constant

Previous Year

AP EAMCET 2021 Paper All AP EAMCET years →

Which of the following statements is incorrect?

Easy

View Solution

If the molar conductivities (in $S \ cm^2 \ mol^{-1}$) of $NaCl$,$KCl$,and $NaOH$ at infinite dilution are $126$,$150$,and $250$,respectively,the molar conductivity of $KOH$ (in $S \ cm^2 \ mol^{-1}$) is

MediumKVPY 2014

View Solution

Calculate the cell constant of a conductivity cell containing $0.1 \ M$ $KCl$ solution having a resistance of $60 \ \Omega$ and a conductivity of $0.014 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ} \ C$. (in $cm^{-1}$)

EasyMHT CET 2024

View Solution

Assertion : On increasing dilution,the specific conductance keeps on increasing.
Reason : On increasing dilution,the degree of ionization of a weak electrolyte increases and the mobility of ions also increases.

MediumAIIMS 2015

View Solution

Write a note on the difficulties associated with the measurement of resistivity of an ionic solution.

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

If the resistance of $0.1 \ M \ KCl$ solution in a conductance cell is $300 \ \Omega$ and conductivity is $0.013 \ S \ cm^{-1}$,then the value of cell constant is

Similar Questions

Which of the following statements is incorrect?

If the molar conductivities (in $S \ cm^2 \ mol^{-1}$) of $NaCl$,$KCl$,and $NaOH$ at infinite dilution are $126$,$150$,and $250$,respectively,the molar conductivity of $KOH$ (in $S \ cm^2 \ mol^{-1}$) is

Calculate the cell constant of a conductivity cell containing $0.1 \ M$ $KCl$ solution having a resistance of $60 \ \Omega$ and a conductivity of $0.014 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ} \ C$. (in $cm^{-1}$)

Assertion : On increasing dilution,the specific conductance keeps on increasing.Reason : On increasing dilution,the degree of ionization of a weak electrolyte increases and the mobility of ions also increases.

Write a note on the difficulties associated with the measurement of resistivity of an ionic solution.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : On increasing dilution,the specific conductance keeps on increasing.
Reason : On increasing dilution,the degree of ionization of a weak electrolyte increases and the mobility of ions also increases.