If the sets A and B are defined as A = { (x, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To find the intersection $A \cap B$,we need to find the points $(x, y)$ that satisfy both equations simultaneously.Given equations are $y = \frac{

Vedclass · Accepted Answer

$A \cap B = \phi$

Vedclass · Answer

(C) To find the intersection $A \cap B$,we need to find the points $(x, y)$ that satisfy both equations simultaneously.Given equations are $y = \frac{1}{x}$ and $y = -x$.Substituting the value of $y$ from the second equation into the first,we get $-x = \frac{1}{x}$.This simplifies to $-x^2 = 1$,or $x^2 = -1$.Since $x$ must be a real number $(x \in R)$,the equation $x^2 = -1$ has no real solutions because the square of any real number is non-negative.Therefore,there are no points $(x, y)$ that belong to both sets $A$ and $B$.Hence,$A \cap B = \phi$.

If the sets $A$ and $B$ are defined as $A = \{ (x, y) : y = \frac{1}{x}, x \in R, x \neq 0 \}$ and $B = \{ (x, y) : y = -x, x \in R \}$,then:

Similar Questions

In a battle,$70\%$ of the combatants lost one eye,$80\%$ an ear,$75\%$ an arm,$85\%$ a leg,and $x\%$ lost all the four limbs. What is the minimum value of $x$?

Let $A = \{1, 2, 3\}$. The total number of distinct relations that can be defined over $A$ is

There are $80$ families in a small extension area. $20$ percent of these families own a car each. $50$ percent of the remaining families own a motor cycle each. How many families in that extension do not own any vehicle?

If $A$ and $B$ have $n$ elements in common,how many elements do $A \times B$ and $B \times A$ have in common?

Which of the following sets is non-empty?

Vedclass Test Series

Exam Paper Generator

Online Exam Module