If the sides of a triangle are 3, 4, and 5, t | vedclass

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(C) The circumradius of a triangle is the radius of the circle that passes through all its vertices.Given the sides of the triangle are $3$, $4$, and

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$\frac{5}{2}$

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(C) The circumradius of a triangle is the radius of the circle that passes through all its vertices.Given the sides of the triangle are $3$, $4$, and $5$.Since $3^2 + 4^2 = 9 + 16 = 25 = 5^2$, the triangle is a right-angled triangle.For a right-angled triangle, the circumradius $R$ is half of the hypotenuse.The hypotenuse is the longest side, which is $5$.Therefore, the circumradius $R = \frac{	ext{hypotenuse}}{2} = \frac{5}{2}$.

If the sides of a triangle are $3$, $4$, and $5$, then the circumradius of the triangle is

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