If the straight line $8x + 3\sqrt{2}y = 36$ touches the ellipse $\frac{x^2}{9} + \frac{y^2}{4} = 2$ at $(a, b)$,then $a + \sqrt{2}b =$

  • A
    $\frac{36}{5\sqrt{2}}$
  • B
    $\frac{8}{3}$
  • C
    $\frac{12 + 2\sqrt{2}}{3}$
  • D
    $\frac{16}{3}$

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