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(C) Let the two numbers be $x$ and $y$.Given that the sum of the numbers is $x + y = 20$.Given that the difference of the numbers is $x - y = 8$.We kn

Vedclass · Accepted Answer

$160$

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(C) Let the two numbers be $x$ and $y$.Given that the sum of the numbers is $x + y = 20$.Given that the difference of the numbers is $x - y = 8$.We know the algebraic identity for the difference of squares: $x^2 - y^2 = (x + y)(x - y)$.Substituting the given values into the identity:$x^2 - y^2 = (20) 	imes (8)$.$x^2 - y^2 = 160$.Therefore,the difference of their squares is $160$.

If the sum and difference of two numbers are $20$ and $8$ respectively,then the difference of their squares is

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