If the sum of all the coefficients of $(\alpha x^2 - 2x + 1)^{2019}$ is equal to the sum of all the coefficients of $(x - \alpha y)^{2019}$,then $\alpha = $

  • A
    -$1$
  • B
    $0$
  • C
    $1$
  • D
    $2$

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