If the sum of bond orders of O_2^{-} and O_2^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Molecular Orbital Theory $(MOT)$,the bond order is calculated as $\frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons

Vedclass · Accepted Answer

$1.20$

Vedclass · Answer

(A) According to Molecular Orbital Theory $(MOT)$,the bond order is calculated as $\frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.For $O_2$ ($16$ electrons): Bond order = $2.0$.For $O_2^{-}$ ($17$ electrons): Bond order = $1.5$.For $O_2^{2-}$ ($18$ electrons): Bond order = $1.0$.Sum of bond orders of $O_2^{-}$ and $O_2^{2-}$ = $1.5 + 1.0 = 2.5$. Thus,$x = 2.5$.For $O_2^{2+}$ ($14$ electrons): Bond order = $3.0$.We need to express the bond order of $O_2^{2+}$ $(3.0)$ in terms of $x$ $(2.5)$.$3.0 = k 	imes 2.5 \implies k = \frac{3.0}{2.5} = 1.2$.Therefore,the bond order of $O_2^{2+}$ is $1.2x$.

If the sum of bond orders of $O_2^{-}$ and $O_2^{2-}$ is $x$,then bond order of $O_2^{2+}$ will be (in $x$)

Similar Questions

Which of the following species,$O_2$,$O_2^+$,and $O_2^-$,has the lowest bond order?

The bond dissociation energy $(E)$ and bond length $(R)$ of $O_2$,$N_2$,and $F_2$ follow the order as:

Write the electron configuration,bond order,and magnetic property of the hydrogen $(H_2)$ molecule.

Which of the following species is paramagnetic?

Which of the following molecules has two unpaired $e^-$ with a bond order equal to $2$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module