If the temperature of a black body is doubled,the frequency at which the spectral intensity becomes maximum will be

The wavelength of maximum energy released during an atomic explosion was $2.93 \times 10^{-10} \ m$. Given that Wien's constant is $b = 2.93 \times 10^{-3} \ m \cdot K$,the maximum temperature attained must be of the order of:

Wien's displacement law expresses the relation between:

The plots of intensity $(I)$ versus wavelength $(\lambda)$ for three black bodies at temperatures $T_1, T_2$ and $T_3$ respectively are as shown. Their temperatures are such that:

Write the temperature of the surfaces of the Moon and the Sun according to Wien's displacement law.

Black bodies $A$ and $B$ radiate maximum energy with wavelength difference $4 \mu m$. The absolute temperature of body $A$ is $3$ times that of $B$. The wavelength at which body $B$ radiates maximum energy is (in $\mu m$)