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(D) We know that,$q = i 	imes t$,where $q$ is the charge in Coulombs,$i$ is the current in Amperes,and $t$ is the time in seconds.$q = 10.7 \ A 	ime

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$\frac{M}{4}$

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(D) We know that,$q = i 	imes t$,where $q$ is the charge in Coulombs,$i$ is the current in Amperes,and $t$ is the time in seconds.$q = 10.7 \ A 	imes 10 \ h 	imes 3600 \ s \ h^{-1} = 385,200 \ C$.Since $96,500 \ C$ corresponds to $1$ mole of electrons,the number of moles of electrons is $\frac{385,200}{96,500} \approx 4$.Since $4$ moles of electrons are required to deposit $1$ mole of metal $M$,the valency of the metal is $4$.Equivalent weight $= \frac{	ext{Atomic weight}}{	ext{Valency}} = \frac{M}{4}$.

If the total electricity required to deposit $1$ mole of a metal $M$ is equal to that of $10.7$ amperes of current for $10$ hours,the equivalent weight of the metal is (atomic weight $= M \ u$):

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