(C) Given,number of observations $n = 20$,$\sum x_i = 1000$,and $\sum x_i^2 = 84000$. The mean $\overline{x} = \frac{\sum x_i}{n} = \frac{1000}{20} =

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(C) Given,number of observations $n = 20$,$\sum x_i = 1000$,and $\sum x_i^2 = 84000$. The mean $\overline{x} = \frac{\sum x_i}{n} = \frac{1000}{20} = 50$. The variance $\sigma^2$ is given by the formula: $\sigma^2 = \frac{1}{n} \sum x_i^2 - (\overline{x})^2$. Substituting the values: $\sigma^2 = \frac{84000}{20} - (50)^2$. $\sigma^2 = 4200 - 2500$. $\sigma^2 = 1700$.

Class 11 Mathematics Statistics Variance and Standard Deviation

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If the total number of observations is $n = 20$,$\sum x_i = 1000$ and $\sum x_i^2 = 84000$,then the variance of the distribution is

AP EAMCET 2022 All AP EAMCET

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$1500$
B
$1600$
C
$1700$
D
$1800$

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If the total number of observations is $n = 20$,$\sum x_i = 1000$ and $\sum x_i^2 = 84000$,then the variance of the distribution is

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