If the truth value of the compound statement | vedclass

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(C) $1$. $A$ conditional statement $A 	o B$ is $False$ only when $A$ is $True$ and $B$ is $False$.$2$. Here, $A = [(p \lor q) \land (q 	o r) \land (

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$(F, T)$

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(C) $1$. $A$ conditional statement $A 	o B$ is $False$ only when $A$ is $True$ and $B$ is $False$.$2$. Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r)]$ and $B = (p \land q)$.$3$. Since $B = (p \land q)$ is $False$, we have $p \land q = F$.$4$. Since $A$ is $True$, all components must be $True$: $(p \lor q) = T$, $(q 	o r) = T$, and $(\sim r) = T$.$5$. From $(\sim r) = T$, we get $r = F$.$6$. Substituting $r = F$ into $(q 	o r) = T$, we get $(q 	o F) = T$, which implies $q = F$.$7$. Substituting $q = F$ into $(p \lor q) = T$, we get $(p \lor F) = T$, which implies $p = T$.$8$. Now, check $p \land q = T \land F = F$, which matches our condition.$9$. Finally, $p 	o q = T 	o F = F$ and $q 	o p = F 	o T = T$.$10$. Thus, the truth values are $(F, T)$.

If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is $False$, then the truth values of $p \to q$ and $q \to p$ are respectively......

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