If the uncertainty in velocity of electron $(\Delta v)$ is $0.1 \ m/s$,the uncertainty in its position $(\Delta x)$ is (given: $m_e = 9.1 \times 10^{-31} \ kg$)

Choose the correct statement.

The uncertainty in the position of an electron $(mass = 9.1 \times 10^{-28} \ g)$ moving with a velocity of $3.0 \times 10^4 \ cm \ s^{-1}$ accurate up to $0.001\%$ will be ................. $cm$ (Use $\frac{h}{4\pi}$ in the uncertainty expression,where $h = 6.626 \times 10^{-27} \ erg \ s$)

Calculate the mass of an elementary particle,which is accelerated to twice the velocity of light with the precision $\pm 1 \%$,and has $1.05 \times 10^{-13} \ m$ uncertainty in position. $(h = 6.6 \times 10^{-34} \ kg \ m^2 \ s^{-1})$

If the position of the electron was measured with an accuracy of $\pm 0.002 \ nm$,the uncertainty in the momentum of it would be (in $kg \ ms^{-1}$) $(h=6.626 \times 10^{-34} \ J \ s)$.

Given: The mass of an electron is $9.1 \times 10^{-31} \ kg$,Planck's constant is $6.62 \times 10^{-34} \ J \cdot s$. The uncertainty involved in the measurement of velocity within a distance of $0.1 \ \mathring{A}$ is: