(A) Work is defined as the product of force and displacement (length): $W = F \times d$.If the unit of force $F$ is increased by $4$ times,the new for

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(A) Work is defined as the product of force and displacement (length): $W = F \times d$.If the unit of force $F$ is increased by $4$ times,the new force $F' = 4F$.If the unit of length $d$ is increased by $4$ times,the new displacement $d' = 4d$.The new unit of energy $W'$ will be: $W' = F' \times d' = (4F) \times (4d) = 16 \times (F \times d) = 16W$.Therefore,the unit of energy is increased by $16$ times.

Class 11 Physics Units and Measurements Mix Examples-Units, Dimensions and Measurement

Medium

If the unit of force and length each be increased by four times,then the unit of energy is increased by $...$ times.

A
$16$
B
$8$
C
$2$
D
$4$

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Class 11 Questions

Class 11

Physics Questions

Chapter

Units and Measurements

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Mix Examples-Units, Dimensions and Measurement

Match the following (Take the relative strength of the strongest fundamental forces in nature as $1$):
$I$ (Fundamental forces in nature) $II$ (Relative strength)
$(A)$ Strong nuclear force $(e)$ $10^{-2}$
$(B)$ Weak nuclear force $(f)$ $1$
$(C)$ Electromagnetic force $(g)$ $10^{10}$
$(D)$ Gravitational force $(h)$ $10^{-13}$
$(i)$ $10^{-39}$

The correct match is:

$I$ (Fundamental forces in nature)	$II$ (Relative strength)
$(A)$ Strong nuclear force	$(e)$ $10^{-2}$
$(B)$ Weak nuclear force	$(f)$ $1$
$(C)$ Electromagnetic force	$(g)$ $10^{10}$
$(D)$ Gravitational force	$(h)$ $10^{-13}$
	$(i)$ $10^{-39}$