If the wavelength and the distance traveled b | vedclass

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Question

(A) According to the de Broglie relation,the wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$.Given that the distance traveled in $1 \ s$ is

Vedclass · Accepted Answer

$2.7 	imes 10^{-2} \ m \ s^{-1}$

Vedclass · Answer

(A) According to the de Broglie relation,the wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$.Given that the distance traveled in $1 \ s$ is equal to the wavelength,we have $d = v 	imes t = v 	imes 1 = v$.Thus,$\lambda = v$.Substituting this into the de Broglie equation: $v = \frac{h}{mv}$,which implies $v^2 = \frac{h}{m}$.Here,$h = 6.626 	imes 10^{-34} \ J \ s$ and $m = 9.11 	imes 10^{-31} \ kg$.$v^2 = \frac{6.626 	imes 10^{-34}}{9.11 	imes 10^{-31}} \approx 7.27 	imes 10^{-4} \ m^2 \ s^{-2}$.Taking the square root,$v = \sqrt{7.27 	imes 10^{-4}} \approx 2.7 	imes 10^{-2} \ m \ s^{-1}$.

If the wavelength and the distance traveled by an electron in $1 \ s$ are the same,calculate its velocity.

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