If the wavelength of a photon is 4000 text{ Å | vedclass

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(A) The wavelength of the photon is given as $\lambda = 4000 	ext{ Å} = 4000 	imes 10^{-10} 	ext{ m} = 4 	imes 10^{-7} 	ext{ m}$.The energy $E$ o

Vedclass · Accepted Answer

$4.95 	imes 10^{-19} 	ext{ J}$

Vedclass · Answer

(A) The wavelength of the photon is given as $\lambda = 4000 	ext{ Å} = 4000 	imes 10^{-10} 	ext{ m} = 4 	imes 10^{-7} 	ext{ m}$.The energy $E$ of a photon is calculated using the formula $E = \frac{hc}{\lambda}$,where $h = 6.626 	imes 10^{-34} 	ext{ J s}$ is Planck's constant and $c = 3 	imes 10^8 	ext{ m/s}$ is the speed of light.Substituting the values:$E = \frac{6.626 	imes 10^{-34} 	imes 3 	imes 10^8}{4 	imes 10^{-7}}$$E = \frac{19.878 	imes 10^{-26}}{4 	imes 10^{-7}}$$E = 4.9695 	imes 10^{-19} 	ext{ J}$Rounding to the nearest provided option,we get $E \approx 4.95 	imes 10^{-19} 	ext{ J}$.

If the wavelength of a photon is $4000 \text{ Å}$,then its energy will be

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