(B) The number of waves $N$ in a given length $L$ is calculated by the formula: $N = \frac{L}{\lambda}$.Given:Length $L = 1 \text{ mm} = 10^{-3} \text

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(B) The number of waves $N$ in a given length $L$ is calculated by the formula: $N = \frac{L}{\lambda}$.Given:Length $L = 1 \text{ mm} = 10^{-3} \text{ m}$.Wavelength $\lambda = 4000 \text{ Å} = 4000 \times 10^{-10} \text{ m} = 4 \times 10^{-7} \text{ m}$.Substituting the values:$N = \frac{10^{-3}}{4 \times 10^{-7}}$$N = \frac{1}{4} \times 10^{-3 - (-7)}$$N = 0.25 \times 10^4$$N = 2500$.Therefore, the number of waves is $2500$.

Class 12 Physics Wave Optics Wave Nature and Interference of Light (Intensity)

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If the wavelength of light is $4000 \text{ Å}$, then the number of waves in $1 \text{ mm}$ length will be . . . . . . -

GUJCET 2015 All GUJCET

A
$25$
B
$2500$
C
$250$
D
$25000$

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Wave Optics

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Wave Nature and Interference of Light (Intensity)

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If the wavelength of light is $4000 \text{ Å}$, then the number of waves in $1 \text{ mm}$ length will be . . . . . . -

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