If there are 999 bases in an RNA that code fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The genetic code is a triplet,meaning $1$ codon consists of $3$ bases.When a base at position $901$ is deleted,it causes a frameshift mutation fro

Vedclass · Accepted Answer

$33$

Vedclass · Answer

(B) The genetic code is a triplet,meaning $1$ codon consists of $3$ bases.When a base at position $901$ is deleted,it causes a frameshift mutation from that point onwards.The total number of bases remaining after the deletion is $998$.The number of bases from the point of deletion $(901)$ to the end of the $RNA$ is $999 - 901 + 1 = 99$ bases.Since each codon consists of $3$ bases,the number of codons affected by this frameshift is $99 / 3 = 33$ codons.Therefore,$33$ codons will be altered.

If there are $999$ bases in an $RNA$ that code for a protein with $333$ amino acids,and the base at position $901$ is deleted such that the length of the $RNA$ becomes $998$ bases,how many codons will be altered?

Similar Questions

Who proposed the 'one gene one enzyme' hypothesis?

$A$ mature $mRNA$ consists of $900$ bases without any stop codon in between. Calculate the number of amino acids coded by this $mRNA$ during translation.

How many nonsense codons are there?

The genetic codes for arginine are:

Which of the following options represents the stop codons (termination signals) in the genetic code?

Vedclass Test Series

Exam Paper Generator

Online Exam Module