If three elements $A, B, C$ crystallize in a cubic solid lattice with $B$ atoms at the cubic centers, $C$ atoms at the center of edges, and $A$ atoms at the corners, then the formula of the compound is
- A$AB_3C$
- B$A_3BC$
- C$ABC_3$
- D$ABC$
Explore More
Similar Questions
The tetrahedral voids formed by $ccp$ arrangement of $Cl^{-}$ ions in rock salt structure are
Medium
View SolutionArgon crystallizes in such a way that the positions of the atoms are at $(0, 0, 0)$,$(0, 1/2, 1/2)$,$(1/2, 0, 1/2)$,and $(1/2, 1/2, 0)$. The type of unit cell is:
Difficult
View SolutionIf $a$ is the length of the side of a cube,the distance between the body-centered atom and one corner atom in the cube will be
MediumNEET 2014
View SolutionIn a solid $AB$ having the $NaCl$ structure,$A$ atoms occupy the corners of the cubic unit cell. If all the face-centered atoms along one of the axes are removed,then the resultant stoichiometry of the solid is
DifficultIIT 2001
View Solution$A^{+}B^{-}$ shows rock salt type arrangement. Edge length of unit cell is $6 \ \mathring{A}$. If radius of $A^{+}$ is $1 \ \mathring{A}$,then the incorrect option is:
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo