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(B) The total number of cards in a deck is $52$, and the number of aces is $4$. When the first card is drawn, the probability of getting an ace is $P(

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$\frac{1}{221}$

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(B) The total number of cards in a deck is $52$, and the number of aces is $4$. When the first card is drawn, the probability of getting an ace is $P(A_1) = \frac{4}{52} = \frac{1}{13}$. Since the card is drawn without replacement, there are now $51$ cards left in the deck, and $3$ of them are aces. The probability of drawing a second ace, given that the first card was an ace, is $P(A_2|A_1) = \frac{3}{51} = \frac{1}{17}$. The probability that both cards are aces is $P(A_1 \cap A_2) = P(A_1) 	imes P(A_2|A_1)$. $P(A_1 \cap A_2) = \frac{1}{13} 	imes \frac{1}{17} = \frac{1}{221}$.

If two cards are drawn one after the other without replacement from a well-shuffled ordinary deck of $52$ cards, then the probability that both of them are aces is

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